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Question:
If alpha and beeta are the zeroes of the quadratic polynomial f(x)=x^2-px+ q the find the value alpha^2+ beeta^2
Answer:

Given, quadratic polynomial is f(x) = x2 - px + q

Now, α and β are the zeroes of the polynomial.

So, α + β = -(-p)

=> α + β = p

and α * β = q

Now, α2 + β2 = (α + β)2 - 2 *α * β

=> α2 + β2 = p2 - 2 *q

=> α2 + β2 = p2 - 2q

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